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fixed trie_hash panic when he was processing duplicates

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This commit is contained in:
debris 2015-12-02 12:57:25 +01:00
parent 706428acbe
commit 18a6090ce5
1 changed files with 15 additions and 7 deletions
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20
src/triehash.rs
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@ -32,12 +32,12 @@ pub fn ordered_trie_root(input: Vec<Vec<u8>>) -> H256 {
.into_iter()
.fold(BTreeMap::new(), | mut acc, vec | {
let len = acc.len();
acc.insert(as_nibbles(&rlp::encode(&len)), vec);
acc.insert(rlp::encode(&len), vec);
acc
})
// then move them to a vector
.into_iter()
.map(|p| p )
.map(|(k, v)| (as_nibbles(&k), v) )
.collect();
gen_trie_root(gen_input)
@ -62,9 +62,15 @@ pub fn ordered_trie_root(input: Vec<Vec<u8>>) -> H256 {
/// assert_eq!(trie_root(v), H256::from_str(root).unwrap());
/// }
/// ```
pub fn trie_root(mut input: Vec<(Vec<u8>, Vec<u8>)>) -> H256 {
input.sort();
pub fn trie_root(input: Vec<(Vec<u8>, Vec<u8>)>) -> H256 {
let gen_input = input
// first put elements into btree to sort them and to remove duplicates
.into_iter()
.fold(BTreeMap::new(), | mut acc, (k, v) | {
acc.insert(k, v);
acc
})
// then move them to a vector
.into_iter()
.map(|(k, v)| (as_nibbles(&k), v) )
.collect();
@ -139,6 +145,7 @@ fn as_nibbles(bytes: &[u8]) -> Vec<u8> {
fn hash256rlp(input: &[(Vec<u8>, Vec<u8>)], pre_len: usize, stream: &mut RlpStream) {
let inlen = input.len();
//println!("input: {:?}", input);
// in case of empty slice, just append empty data
if inlen == 0 {
stream.append_empty_data();
@ -167,6 +174,7 @@ fn hash256rlp(input: &[(Vec<u8>, Vec<u8>)], pre_len: usize, stream: &mut RlpStre
cmp::min(key.shared_prefix_len(&k), acc)
});
println!("shared_prefix: {}, prefix_len: {}", shared_prefix, pre_len);
// if shared prefix is higher than current prefix append its
// new part of the key to the stream
// then recursively append suffixes of all items who had this key
@ -192,8 +200,8 @@ fn hash256rlp(input: &[(Vec<u8>, Vec<u8>)], pre_len: usize, stream: &mut RlpStre
// cout how many successive elements have same next nibble
let len = match begin < input.len() {
true => input[begin..].iter()
.map(| pair | pair.0[pre_len] )
.take_while(|&q| q == i).count(),
.take_while(| pair | { println!("{:?}", pair.0); pair.0[pre_len] == i }).count(),
//.take_while(|&q| q == i).count(),
false => 0
};